Find all real solutions of \(\left(x^2-7x+11\right)^{\left(x^2-11x+30\right)}=1\)

13 days ago by

First thing I noticed was the exponent can be factorised \(x^2-11x+30=(x-5)(x-6)\)

But I don't know what to do from here
Community: Everyday Math

1 Answer

13 days ago by
Remember that any number (except 0) to the power of 0 is 1.

Which means if  \(x^2-11x+30=0\)  \(\left(x^2-7x+11\right)^{\left(x^2-11+30\right)}=1\)

Also remember that 1 to the power of any number is 1.

So the second case will be:  \(x^2-7x+11=1\)

And there is one more case, -1 to the power of even number is 1.

So the final case will be  \(x^2-7x+11=-1\), where \(x^2-11x+30\) is even
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